Math Problem Statement

Construct the truth table for the statement form (p ∨ q) ∧ ~(p ∧ q)

Solution

The problem requires constructing a truth table for the statement:

(pq)(pq)(p \lor q) \land \sim (p \land q)

Here are the steps to construct the truth table:

  1. Columns for pp and qq: These represent all possible truth values of the variables.
  2. Intermediate expressions: Include pqp \lor q (disjunction), pqp \land q (conjunction), and (pq)\sim (p \land q) (negation).
  3. Final expression: Combine the results of pqp \lor q and (pq)\sim (p \land q) using the conjunction operator (\land).

Let me construct this table.

ppqqpqp \lor qpqp \land q(pq)\sim (p \land q)(pq)(pq)(p \lor q) \land \sim (p \land q)
TTTTFF
TFTFTT
FTTFTT
FFFFTF

Explanation:

  1. pqp \lor q: True if either pp or qq is true.
  2. pqp \land q: True if both pp and qq are true.
  3. (pq)\sim (p \land q): The negation of pqp \land q; true if pqp \land q is false.
  4. Final expression: True if both pqp \lor q and (pq)\sim (p \land q) are true.

Would you like further clarification or additional details?


Follow-up questions:

  1. What is the significance of the negation in the statement form?
  2. How does the conjunction (\land) affect the final truth table outcomes?
  3. Can this logic statement be expressed using another logical equivalence?
  4. How would the truth table change if the \lor was replaced by a \land?
  5. What practical applications can such logical constructs have?

Tip: For complex logical statements, always break them into smaller components to simplify truth table construction.

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Math Problem Analysis

Mathematical Concepts

Logic
Truth Tables
Propositional Logic

Formulas

Disjunction (p ∨ q): True if at least one of p or q is true
Conjunction (p ∧ q): True only if both p and q are true
Negation (¬): Inverts the truth value of a statement

Theorems

Boolean Algebra

Suitable Grade Level

Grades 9-12