Math Problem Statement

Construct a truth table for the given logical statement [p ∧ (q ∨ ¬p)] ∨ r.

Solution

Let's construct the truth table for the given logical statement:

[p(q¬p)]r[p \land (q \lor \neg p)] \lor r

To solve this, we will evaluate step by step. The columns you need to fill are:

  1. ¬p\neg p (the negation of pp)
  2. q¬pq \lor \neg p (the disjunction of qq and ¬p\neg p)
  3. p(q¬p)p \land (q \lor \neg p) (the conjunction of pp with the previous result)
  4. [p(q¬p)]r[p \land (q \lor \neg p)] \lor r (the final disjunction with rr)

Let's break this down row by row, based on all possible truth values for pp, qq, and rr (True = T, False = F):

ppqqrr¬p\neg pq¬pq \lor \neg pp(q¬p)p \land (q \lor \neg p)[p(q¬p)]r[p \land (q \lor \neg p)] \lor r
TTTFTTT
TTFFTTT
TFTFFFT
TFFFFFF
FTTTTFT
FTFTTFF
FFTTTFT
FFFTTFF

Detailed Explanation:

  1. ¬p\neg p is just the negation of pp.
  2. q¬pq \lor \neg p combines the value of qq and the negation of pp using logical "or."
  3. p(q¬p)p \land (q \lor \neg p) takes the value of pp and the result of q¬pq \lor \neg p using logical "and."
  4. [p(q¬p)]r[p \land (q \lor \neg p)] \lor r combines the previous result with rr using logical "or."

Would you like a more detailed explanation or have any questions about this?

Here are 5 follow-up questions related to this topic:

  1. How do you determine the negation of a variable in a truth table?
  2. What is the difference between conjunction (\land) and disjunction (\lor)?
  3. How do you know when a complex statement is true or false?
  4. Can you find a scenario where a complex logical statement simplifies to a single truth value?
  5. How would the truth table change if one of the operators was replaced with a conditional (→)?

Tip: Breaking complex logical statements into smaller components can make evaluating them easier, especially when building truth tables.

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Math Problem Analysis

Mathematical Concepts

Logic
Truth Tables

Formulas

¬p (negation of p)
q ∨ ¬p (disjunction)
p ∧ (q ∨ ¬p) (conjunction)
[p ∧ (q ∨ ¬p)] ∨ r (final disjunction)

Theorems

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Suitable Grade Level

Grades 10-12