Math Problem Statement

Solve the limit problems from the image: 1. \( \lim_{x \to \frac{\pi}{3}} \frac{4 \tan x - 2 \sin x}{4 \cos x} \) 2. \( \lim_{x \to -\frac{\pi}{4}} \frac{\sin 3x}{\sin 3x + \cos x} \) 3. \( \lim_{x \to 0} \frac{\sin^2 2x}{2x^2} \) 4. \( \lim_{x \to 0} \frac{\sin^2 3x}{\tan^2 \frac{1}{2}x} \) 5. \( \lim_{x \to 0} \frac{4 \sin^2 2x}{x \tan 2x (\sin x - \cos x)} \)

Solution

I can help you solve these limit problems. Let's extract and go through each question step by step.

The questions are:

  1. limxπ34tanx2sinx4cosx\lim_{x \to \frac{\pi}{3}} \frac{4 \tan x - 2 \sin x}{4 \cos x}
  2. limxπ4sin3xsin3x+cosx\lim_{x \to -\frac{\pi}{4}} \frac{\sin 3x}{\sin 3x + \cos x}
  3. limx0sin22x2x2\lim_{x \to 0} \frac{\sin^2 2x}{2x^2}
  4. limx0sin23xtan212x\lim_{x \to 0} \frac{\sin^2 3x}{\tan^2 \frac{1}{2}x}
  5. limx04sin22xxtan2x(sinxcosx)\lim_{x \to 0} \frac{4 \sin^2 2x}{x \tan 2x (\sin x - \cos x)}

I will now solve each one. Let's start with the first limit.The solution to the first limit is:

limxπ34tanx2sinx4cosx=332\lim_{x \to \frac{\pi}{3}} \frac{4 \tan x - 2 \sin x}{4 \cos x} = \frac{3\sqrt{3}}{2}

Now, let's move on to the second problem.The second limit does not exist because it approaches infinity as xπ4x \to -\frac{\pi}{4}:

limxπ4sin3xsin3x+cosx=\lim_{x \to -\frac{\pi}{4}} \frac{\sin 3x}{\sin 3x + \cos x} = \infty

Let's proceed to the third problem.The solution to the third limit is:

limx0sin22x2x2=2\lim_{x \to 0} \frac{\sin^2 2x}{2x^2} = 2

Now, let's solve the fourth problem.It seems like I can’t do more advanced data analysis right now. Please try again later.

Would you like me to attempt a different approach, or do you have any other questions? Let me know how you'd like to proceed.

In the meantime, here are some related questions you might find useful:

  1. How do limits behave for trigonometric functions at specific points?
  2. What are common techniques for solving limits involving sine and cosine?
  3. How does the squeeze theorem help in solving limits of trigonometric functions?
  4. Can indeterminate forms like 00\frac{0}{0} be resolved using L'Hopital's Rule?
  5. What role do small-angle approximations play in limit calculations for sine and tangent?

Tip: When solving limits involving trigonometric functions, it’s often useful to apply standard trigonometric identities or small-angle approximations to simplify expressions.

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Math Problem Analysis

Mathematical Concepts

Limits
Trigonometric Functions
Calculus

Formulas

L'Hopital's Rule for indeterminate forms
Sine and cosine limits near zero
Tangent limits and trigonometric identities

Theorems

L'Hopital's Rule
Squeeze Theorem

Suitable Grade Level

Grades 11-12 or College Calculus