The problem involves determining the number of triangles that can be formed using diagonals from a common vertex in a regular hexagon.

Solution:

1. A hexagon has 6 sides, which means it has 6 vertices.
2. To form triangles from one vertex, we connect that vertex to two other vertices.
3. Exclude the vertex itself and its two adjacent vertices (as those form edges, not diagonals). This leaves 3 vertices to connect with the chosen vertex.
4. Thus, the number of triangles that can be formed is:

$\text{Number of triangles} = 6 - 2 - 1 = 3$

Final Answer:

3 triangles.

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Related Questions:

1. How do you calculate the total number of diagonals in a polygon?
2. What is the formula for the sum of interior angles of a hexagon?
3. How many diagonals does a hexagon have?
4. Can you use this method to find the number of triangles in an octagon?
5. What is the relationship between a polygon's sides and the number of triangles formed from one vertex?

Tip:

For any polygon, the number of triangles formed by connecting diagonals from one vertex is always $n - 2$, where $n$ is the number of sides.