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To determine how many triangles a pentagon can be divided into by drawing all diagonals from one vertex, we can use a formula for any polygon. The number of triangles formed is given by:

\[
\text{Number of triangles} = n - 2
\]

where \( n \) is the number of sides of the polygon.

In this case, a pentagon has 5 sides (\( n = 5 \)):

\[
\text{Number of triangles} = 5 - 2 = 3
\]

Thus, the correct answer is:

**A. 3**

Would you like more details or have any questions?

Here are 5 related questions for you to explore:
1. How many triangles can be formed from a vertex in a hexagon?
2. What is the relationship between the number of sides in a polygon and the number of diagonals?
3. How do you calculate the interior angle sum of a polygon?
4. How do you determine the number of diagonals in a polygon?
5. How many diagonals are there in a regular octagon?

**Tip:** For any \( n \)-sided polygon, the formula to find the number of triangles formed from one vertex is \( n - 2 \).

A pentagon can be divided into how many triangles by drawing all of the diagonals from one vertex?

Explore how to divide a pentagon into triangles by drawing diagonals from one vertex. Learn the key formula (n - 2) to determine the number of triangles formed from polygons. This geometry problem is suitable for students in Grades 6-8.

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