https://file.aiquickdraw.com/mathbot/file/17288765766788bar55oz.jpg

The polygon shown in the image is a hexagon (6-sided polygon). The question asks how many triangles can be formed by drawing diagonals from a common vertex.

In a polygon with \( n \) sides, the number of triangles that can be formed by drawing diagonals from a single vertex is given by the formula:

\[
\text{Number of triangles} = n - 2
\]

Here, \( n = 6 \) because it's a hexagon. Applying the formula:

\[
\text{Number of triangles} = 6 - 2 = 4
\]

So, you can form 4 triangles by drawing diagonals from any one vertex of the hexagon.

Would you like further details or have any other questions? Here are some related questions for further exploration:

1. How many diagonals can be drawn in a hexagon?
2. What is the general formula for the number of diagonals in an \( n \)-sided polygon?
3. How does the method change for polygons with more or fewer sides?
4. Can you divide any polygon into triangles using diagonals?
5. What would be the total interior angle sum for a hexagon?

**Tip:** When working with polygons, it’s often useful to remember that the number of diagonals increases as the number of sides increases!

Using diagonals from a common vertex, how many triangles could be formed from the polygon pictured below?

Learn how to calculate the number of triangles formed from a single vertex in a hexagon using diagonals. Understand key polygon geometry concepts with an easy-to-follow formula: Number of triangles = n - 2. This problem is ideal for students in Grades 6-8.

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