Math Problem Statement

Write an equation for a function that has the graph with the shape of yequals=StartRoot x EndRootx​, but reflected across the​ y-axis and shifted rightright 88 units and upup 55

Solution

To write an equation for the function that follows these transformations, we'll start with the base function:

y=xy = \sqrt{x}

Now, let's apply the specified transformations:

  1. Reflection across the y-axis: To reflect a function across the y-axis, we replace xx with x-x. This gives: y=xy = \sqrt{-x}

  2. Shift 8 units to the right: To shift the graph to the right by 8 units, we replace xx with x8x - 8. Applying this to the current function: y=(x8)y = \sqrt{-(x - 8)} Simplifying this: y=8xy = \sqrt{8 - x}

  3. Shift 5 units up: To shift the graph up by 5 units, we add 5 to the function: y=8x+5y = \sqrt{8 - x} + 5

Thus, the final equation for the function is: y=8x+5y = \sqrt{8 - x} + 5

Would you like any further details or clarifications on this? Here are 5 questions to explore further:

  1. How do you reflect a function across the x-axis?
  2. What happens if you shift a function left instead of right?
  3. What if you combined vertical and horizontal stretches with these transformations?
  4. How would this function change if you reflected it across the x-axis instead?
  5. How can you identify these transformations visually on a graph?

Tip: When reflecting a function across the y-axis, always replace xx with x-x inside the function.

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Math Problem Analysis

Mathematical Concepts

Function Transformations
Square Root Functions
Reflections
Translations

Formulas

y = √x
y = f(-x) for reflection across the y-axis
y = f(x - h) for horizontal shifts
y = f(x) + k for vertical shifts

Theorems

Transformation of Functions
Reflection Theorem
Translation Theorem

Suitable Grade Level

Grades 9-11