We are given the function $f(x) = \sqrt{-(x - 2)}$. Let's break down how this function is transformed from a standard toolkit function, which is typically $\sqrt{x}$.

1. Reflection: The negative sign inside the square root indicates a reflection across the y-axis. This is because the term $-(x - 2)$ can be rewritten as $-x + 2$, and negating the $x$-values reflects the graph across the vertical axis.

2. Shift: The term $(x - 2)$ indicates a horizontal shift. Specifically, this represents a rightward shift by 2 units because when $x = 2$, the expression inside the square root is zero.

Conclusion:

The transformation involves a shift right by 2 units and a reflection across the y-axis.

The correct option is:

• Shift right 2 unit(s), reflect across the y-axis.

Would you like more details or explanations? Here are some related questions:

1. How would the graph change if the negative sign were outside the square root?
2. What if the function had a vertical shift as well, say $\sqrt{-(x-2)} + 3$?
3. How does the transformation change if the sign inside the square root is positive?
4. How can you find the domain of this transformed function?
5. What happens to the range of the function after the reflection?

Tip: When analyzing transformations, always observe shifts (horizontal/vertical) and reflections (over the x- or y-axis) first!