Math Problem Statement

The graph of f(x)=(square root of x) is given below. Write the equation of a function h(x) which would first shift the graph down 6 units then reflect it over the x-axis

Solution

To find the equation of the function h(x)h(x) that transforms the graph of f(x)=xf(x) = \sqrt{x}, we need to apply two transformations:

  1. Shift down by 6 units: This transformation subtracts 6 from the original function. So the new function becomes: f(x)6=x6f(x) - 6 = \sqrt{x} - 6

  2. Reflect over the x-axis: Reflecting a function over the x-axis involves multiplying the entire function by 1-1. Applying this to the function from step 1: h(x)=(x6)h(x) = -(\sqrt{x} - 6) This simplifies to: h(x)=x+6h(x) = -\sqrt{x} + 6

Thus, the equation of the function h(x)h(x) is: h(x)=x+6h(x) = -\sqrt{x} + 6

Would you like more details or have any questions?

Here are some related questions:

  1. How do you reflect a graph over the y-axis?
  2. What happens to a graph when you shift it left or right?
  3. What are vertical and horizontal stretches and compressions?
  4. How do you shift a graph up or down?
  5. How do multiple transformations (e.g., shifts and reflections) interact with each other?

Tip: When applying multiple transformations to a function, always perform vertical shifts last.

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Math Problem Analysis

Mathematical Concepts

Transformations
Function Shifting
Function Reflection

Formulas

f(x) - 6 = \sqrt{x} - 6 (shift down 6 units)
h(x) = -(\sqrt{x} - 6) (reflect over x-axis)
h(x) = -\sqrt{x} + 6 (final equation)

Theorems

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Suitable Grade Level

Grades 9-11