Math Problem Statement

write the equations from a description: the shape of f(x) = sqrt(x), but shifted 6 units to the left and then reflected in both the x-axis and the y-axis

Solution

To construct the equation based on your description:

  1. Start with the original function: f(x)=xf(x) = \sqrt{x}.
  2. Shift the graph 6 units to the left: Replace xx with x+6x + 6, so we get f(x)=x+6f(x) = \sqrt{x + 6}.
  3. Reflect across the x-axis: Multiply the function by 1-1, resulting in f(x)=x+6f(x) = -\sqrt{x + 6}.
  4. Reflect across the y-axis: Replace xx with x-x, resulting in the final function:

f(x)=x+6f(x) = -\sqrt{-x + 6}

This is the equation for the described transformation of f(x)=xf(x) = \sqrt{x}.

Would you like more details or have any questions? Here are five related questions to deepen understanding:

  1. How does shifting a function left or right affect its domain?
  2. What happens to the range of f(x)f(x) when it's reflected across the x-axis?
  3. How does a reflection across the y-axis impact the behavior of the function?
  4. How would a vertical shift influence the shape and position of f(x)f(x)?
  5. What are the differences between absolute value transformations and reflections?

Tip: When transforming functions, always apply horizontal changes (shifts and reflections) before vertical transformations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Function transformations
Reflections
Shifts

Formulas

f(x) = sqrt(x)
f(x) = sqrt(x + 6)
f(x) = -sqrt(x + 6)
f(x) = -sqrt(-x + 6)

Theorems

Transformation of functions
Reflection across the x-axis and y-axis

Suitable Grade Level

Grades 8-10