Math Problem Statement
Solution
The problem describes a child's savings in a bank where the difference in savings between months is constant. The problem provides the following details:
- First month savings: Rp50,000.00
- Second month savings: Rp55,000.00
- Third month savings: Rp60,000.00
This indicates that the savings increase by Rp5,000.00 each month. This is an arithmetic sequence where:
- First term () = 50,000
- Common difference () = 5,000
We need to find the total savings over 3 years (which is 36 months).
Solution:
The formula for the sum of the first terms in an arithmetic sequence is:
where:
- (first term)
- (common difference)
- (number of months)
Let's calculate the total savings.The total savings of the child over 3 years is Rp 4,950,000.00.
Would you like more details on how this calculation was done, or do you have any other questions?
Related Questions:
- How would the total savings change if the monthly increase was Rp10,000 instead of Rp5,000?
- What would be the savings after 2 years under the same conditions?
- How can we calculate the amount saved in the 24th month?
- If the initial savings were Rp60,000 and the increase was still Rp5,000, what would be the total savings after 3 years?
- How would you calculate the average monthly savings over 3 years?
Tip: Understanding the arithmetic sequence formula is crucial for solving problems involving regularly increasing or decreasing quantities.
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Math Problem Analysis
Mathematical Concepts
Arithmetic Sequence
Summation of Series
Formulas
Sum of arithmetic sequence: Sn = n/2 × (2a + (n-1) × d)
Theorems
Arithmetic sequence summation formula
Suitable Grade Level
Grades 10-12
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