Math Problem Statement

Seorang anak menabung di suatu bank dengan selisih kenaikan tabungan antar bulan tetap. Pada bulan pertama menabung sebesar Rp50.000,00, bulan kedua Rp55.000,00 bulan ketiga Rp60.000,00, dan seterusnya. Besar tabungan anak tersebut selama 3 tahun adalah?

Solution

The problem describes a child's savings in a bank where the difference in savings between months is constant. The problem provides the following details:

  • First month savings: Rp50,000.00
  • Second month savings: Rp55,000.00
  • Third month savings: Rp60,000.00

This indicates that the savings increase by Rp5,000.00 each month. This is an arithmetic sequence where:

  • First term (aa) = 50,000
  • Common difference (dd) = 5,000

We need to find the total savings over 3 years (which is 36 months).

Solution:

The formula for the sum of the first nn terms in an arithmetic sequence is:

Sn=n2×(2a+(n1)×d)S_n = \frac{n}{2} \times (2a + (n-1) \times d)

where:

  • a=50,000a = 50,000 (first term)
  • d=5,000d = 5,000 (common difference)
  • n=36n = 36 (number of months)

Let's calculate the total savings.The total savings of the child over 3 years is Rp 4,950,000.00.

Would you like more details on how this calculation was done, or do you have any other questions?

Related Questions:

  1. How would the total savings change if the monthly increase was Rp10,000 instead of Rp5,000?
  2. What would be the savings after 2 years under the same conditions?
  3. How can we calculate the amount saved in the 24th month?
  4. If the initial savings were Rp60,000 and the increase was still Rp5,000, what would be the total savings after 3 years?
  5. How would you calculate the average monthly savings over 3 years?

Tip: Understanding the arithmetic sequence formula is crucial for solving problems involving regularly increasing or decreasing quantities.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequence
Summation of Series

Formulas

Sum of arithmetic sequence: Sn = n/2 × (2a + (n-1) × d)

Theorems

Arithmetic sequence summation formula

Suitable Grade Level

Grades 10-12