Math Problem Statement

What is the Thévenin equivalent resistance of the circuit to the left of the resistor RL in the circuit below? Give your answer in ohms [Ω].

Solution

To find the Thévenin equivalent resistance RthR_{th} of the circuit to the left of RLR_L, follow these steps:

Step 1: Remove RLR_L

Since we are calculating the Thévenin resistance, we temporarily remove RLR_L from the circuit. This isolates the network to the left of RLR_L, so we can determine the equivalent resistance of that part of the circuit.

Step 2: Deactivate the Voltage Source

Replace the 3V voltage source with a short circuit (effectively making it a wire), because in Thévenin resistance calculations, we deactivate all independent sources.

Step 3: Identify Resistor Combinations

Now, analyze the resistor network with the voltage source shorted:

  1. The 20 Ω\Omega and 30 Ω\Omega resistors at the top are in series: Rtop=20Ω+30Ω=50ΩR_{top} = 20 \Omega + 30 \Omega = 50 \Omega

  2. The 20 Ω\Omega and 30 Ω\Omega resistors at the bottom are also in series: Rbottom=20Ω+30Ω=50ΩR_{bottom} = 20 \Omega + 30 \Omega = 50 \Omega

  3. Now, RtopR_{top}, RbottomR_{bottom}, and the 50 Ω\Omega resistor in the middle are all in parallel. The equivalent resistance RthR_{th} is found using the parallel resistance formula: 1Rth=1Rtop+150Ω+1Rbottom\frac{1}{R_{th}} = \frac{1}{R_{top}} + \frac{1}{50 \Omega} + \frac{1}{R_{bottom}} Substituting the values: 1Rth=150Ω+150Ω+150Ω=350Ω\frac{1}{R_{th}} = \frac{1}{50 \Omega} + \frac{1}{50 \Omega} + \frac{1}{50 \Omega} = \frac{3}{50 \Omega} Rth=50Ω316.67ΩR_{th} = \frac{50 \Omega}{3} \approx 16.67 \Omega

Final Answer

The Thévenin equivalent resistance RthR_{th} is approximately: Rth16.67ΩR_{th} \approx 16.67 \Omega

Would you like further explanation on any part of the calculation?


Further Questions to Explore:

  1. How would you find the Thévenin equivalent voltage across the terminals of RLR_L?
  2. How does removing RLR_L affect the calculation of the Thévenin equivalent?
  3. What changes if we have a current source instead of a voltage source?
  4. Why do we deactivate independent sources when calculating Thévenin resistance?
  5. How would you find the Norton equivalent resistance from this circuit?

Tip: In circuits with multiple resistors, simplify by combining series and parallel resistors step-by-step.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Electric Circuits
Thévenin's Theorem
Resistor Networks

Formulas

Series resistance: R_total = R1 + R2
Parallel resistance: 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn

Theorems

Thévenin's Theorem

Suitable Grade Level

College-level Physics or Electrical Engineering