Math Problem Statement

Determine the unknown values in the system of linear equations for the price of fruits, heights of objects, coin values, and juice mixture volumes.

Solution

Let's analyze the problem set presented in the image.

Problem 1: Price of Fruits

You are given two equations related to the prices of fruits:

  • 1 apple + 1 pineapple costs Rp 10,000
  • 2 apples + 1 pineapple costs Rp 13,000

We need to determine the individual prices of the apple and the pineapple by solving this system of equations.

Let:

  • xx = price of an apple
  • yy = price of a pineapple

From the information:

  1. x+y=10,000x + y = 10,000
  2. 2x+y=13,0002x + y = 13,000

We can solve these two equations simultaneously to find the values of xx and yy.

Problem 2: Heights of Objects

We are asked to determine the heights of the plant and the table, where two configurations of the table and plant heights are provided:

  • The total height of a table with a plant is 160 cm.
  • The height of a table alone is 40 cm.

Let:

  • zz = height of the plant
  • ww = height of the table

From the information:

  1. z+w=160z + w = 160
  2. w=40w = 40

We can substitute the value of ww to find zz.

Problem 3: Coin Values

There are two types of coins available in a game:

  • With Rp 70,000, you can either get:
    • 20 coins of type I and 30 coins of type II, or
    • 25 coins of type I and 20 coins of type II.

Let:

  • aa = value of one coin of type I
  • bb = value of one coin of type II

From the information:

  1. 20a+30b=70,00020a + 30b = 70,000
  2. 25a+20b=70,00025a + 20b = 70,000

We can solve this system of equations to find the values of aa and bb.

Problem 4: Juice Mixture

Initially, there is 300 mL of juice, which is a mixture of orange juice and water. If 20% more orange juice and 50% more water are added, the total becomes 420 mL. We are asked to find the initial amounts of orange juice and water.

Let:

  • oo = initial volume of orange juice
  • ww = initial volume of water

From the information:

  1. o+w=300o + w = 300
  2. 1.2o+1.5w=4201.2o + 1.5w = 420

We can solve this system to find oo and ww.


Would you like me to solve all the systems of equations in detail? Here are 5 follow-up questions to explore:

  1. How do you solve a system of linear equations using substitution?
  2. What is the significance of adding percentages to mixtures in real-life situations?
  3. What method would you use for solving larger systems of equations?
  4. Can you think of a situation where knowing the height of objects like in Problem 2 could be practically useful?
  5. How can unit prices of items be efficiently calculated in business settings?

Tip: When working with systems of equations, it’s helpful to start by simplifying one equation to substitute into the other, especially when one variable is already isolated.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Systems of Equations
Percentage Calculation
Basic Arithmetic

Formulas

x + y = 10,000
2x + y = 13,000
z + w = 160
w = 40
20a + 30b = 70,000
25a + 20b = 70,000
o + w = 300
1.2o + 1.5w = 420

Theorems

Substitution Method
Simultaneous Equation Solving

Suitable Grade Level

Grades 9-11