Math Problem Statement

Find the sum of the first n terms: 1 + 5 + 13 + 29 + 61 + ... n terms.

Solution

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Find the sum of the first nn-terms: 1+5+13+29+61+1 + 5 + 13 + 29 + 61 + \cdots

Analysis of the Sequence:

The sequence provided is: 1,5,13,29,61,1, 5, 13, 29, 61, \dots.

We notice that this sequence grows quite fast, and the differences between consecutive terms are:

  • 51=45 - 1 = 4
  • 135=813 - 5 = 8
  • 2913=1629 - 13 = 16
  • 6129=3261 - 29 = 32

The differences are powers of 2: 4,8,16,32,4, 8, 16, 32, \dots. This suggests that the sequence follows a quadratic pattern.

Formula for the Sequence:

We assume the general term of the sequence is quadratic, i.e., of the form: Tn=an2+bn+cT_n = an^2 + bn + c We can determine the values of aa, bb, and cc using the first few terms of the sequence:

  1. For T1=1T_1 = 1, we have: a(1)2+b(1)+c=1a+b+c=1a(1)^2 + b(1) + c = 1 \quad \Rightarrow \quad a + b + c = 1

  2. For T2=5T_2 = 5, we have: a(2)2+b(2)+c=54a+2b+c=5a(2)^2 + b(2) + c = 5 \quad \Rightarrow \quad 4a + 2b + c = 5

  3. For T3=13T_3 = 13, we have: a(3)2+b(3)+c=139a+3b+c=13a(3)^2 + b(3) + c = 13 \quad \Rightarrow \quad 9a + 3b + c = 13

Now, I will solve this system of equations to find aa, bb, and cc.The solution to the system of equations is: a=2,b=2,c=1a = 2, \quad b = -2, \quad c = 1 Thus, the general term of the sequence is: Tn=2n22n+1T_n = 2n^2 - 2n + 1

Sum of the First nn-terms:

The sum of the first nn-terms of a sequence is given by: Sn=n=1nTnS_n = \sum_{n=1}^{n} T_n Where Tn=2n22n+1T_n = 2n^2 - 2n + 1. I'll calculate the general formula for the sum SnS_n.It seems I attempted to use a symbolic variable in a way that requires an actual integer. Instead, I'll apply the summation formula to find the sum of the sequence's first nn terms using calculus or algebraic methods. Let me correct that.The sum of the first nn-terms of the sequence is given by the formula: Sn=n(2n2+1)3S_n = \frac{n(2n^2 + 1)}{3}

This formula allows you to calculate the sum of the first nn-terms of the sequence.

Do you have any further questions or would you like additional details?

Here are 5 related questions you can explore:

  1. How can this sum formula be derived directly using summation rules?
  2. Can you calculate the sum for a specific nn, say n=5n = 5?
  3. How would the formula change if the sequence started with a different first term?
  4. What if the differences between consecutive terms followed another pattern, such as cubes?
  5. How can we visualize the growth of this sequence?

Tip: Whenever you encounter a sequence, looking at the differences between consecutive terms is a powerful way to guess the pattern!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Sequences
Summation

Formulas

T_n = 2n^2 - 2n + 1
S_n = (n(2n^2 + 1)) / 3

Theorems

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Suitable Grade Level

Grades 10-12