Math Problem Statement

square inside a circle find the area and perimeter.

Square inside a circle find the area and perimeter.

Solution

From the image, we see a square inscribed in a circle. The diagonal of the square is labeled as 222\sqrt{2} units. We need to calculate the area and perimeter of the square.

Step 1: Relationship between the diagonal and side of the square

The diagonal (dd) of a square is related to its side length (ss) by the formula: d=s2.d = s\sqrt{2}. Here, d=22d = 2\sqrt{2}. Substituting this into the formula: 22=s2.2\sqrt{2} = s\sqrt{2}. Divide both sides by 2\sqrt{2}: s=2.s = 2.

Step 2: Area of the square

The area (AA) of a square is given by: A=s2.A = s^2. Substitute s=2s = 2: A=22=4square units.A = 2^2 = 4 \, \text{square units}.

Step 3: Perimeter of the square

The perimeter (PP) of a square is given by: P=4s.P = 4s. Substitute s=2s = 2: P=4×2=8units.P = 4 \times 2 = 8 \, \text{units}.

Final Answer:

  • Area: 4square units4 \, \text{square units}
  • Perimeter: 8units8 \, \text{units}

Would you like a detailed derivation of any step or further assistance?


Related Questions:

  1. How is the diagonal formula derived for a square?
  2. What is the area of the circle enclosing the square?
  3. Can the square's diagonal be used to calculate its perimeter directly?
  4. How would the solution change if the diagonal were 424\sqrt{2}?
  5. What is the ratio of the square's area to the circle's area?

Tip:

Always check whether the diagonal or side of a square is given when solving inscribed or circumscribed problems!

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Math Problem Analysis

Mathematical Concepts

Geometry
Properties of a Square
Properties of a Circle

Formulas

Diagonal of a square: d = s√2
Area of a square: A = s²
Perimeter of a square: P = 4s

Theorems

Pythagoras' Theorem (used to derive the diagonal formula for a square)

Suitable Grade Level

Grades 8-10