Math Problem Statement

A rectangle is inscribed in a circle, such that each vertex of the rectangle lies on the circumference of the circle. The diagonal of the rectangle is twice the length of the shortest side of the rectangle. The area of the rectangle is 1,089√3 square units. What is the length, in units, of the diameter of the circle?

Solution

The problem presented involves a rectangle inscribed in a circle. Here's a breakdown of the given information:

  • A rectangle is inscribed in a circle, meaning each vertex of the rectangle touches the circumference of the circle.
  • The diagonal of the rectangle is twice the length of the shortest side of the rectangle.
  • The area of the rectangle is given as 1,08931,089 \sqrt{3} square units.
  • The goal is to find the length of the diameter of the circle.

Let's break this down step by step:

  1. Rectangle Inscribed in a Circle: If a rectangle is inscribed in a circle, the diagonal of the rectangle is the diameter of the circle. Let's denote the length of the shorter side of the rectangle as aa and the longer side as bb. The diagonal dd can be expressed using the Pythagorean theorem: d=a2+b2d = \sqrt{a^2 + b^2} Since dd is the diameter of the circle, our goal is to find dd.

  2. Given: Diagonal is twice the length of the shorter side: We are told that the diagonal is twice the length of the shortest side, so: d=2ad = 2a

  3. Given: Area of the Rectangle: The area of the rectangle is A=abA = ab, and we are given that: A=1,0893A = 1,089 \sqrt{3} So: ab=1,0893ab = 1,089 \sqrt{3}

  4. Use of Diagonal: From the diagonal equation d=2ad = 2a, we can also write: d2=a2+b2d^2 = a^2 + b^2 Substituting d=2ad = 2a into this: (2a)2=a2+b2(2a)^2 = a^2 + b^2 4a2=a2+b24a^2 = a^2 + b^2 3a2=b23a^2 = b^2 b=3ab = \sqrt{3}a

  5. Substitute into the Area Equation: Now substitute b=3ab = \sqrt{3}a into the area equation ab=1,0893ab = 1,089 \sqrt{3}: a3a=1,0893a \cdot \sqrt{3}a = 1,089 \sqrt{3} 3a2=1,0893\sqrt{3}a^2 = 1,089 \sqrt{3} Cancel 3\sqrt{3} from both sides: a2=1,089a^2 = 1,089 a=1,089=33a = \sqrt{1,089} = 33

  6. Find the Diameter: Since d=2ad = 2a, the diameter of the circle is: d=2×33=66unitsd = 2 \times 33 = 66 \, \text{units}

Final Answer:

The diameter of the circle is 66 units.


Do you have any questions, or would you like further details on any part of the solution?

Here are 5 related questions to expand your understanding:

  1. What is the relationship between the diagonal of a rectangle and the circle in which it is inscribed?
  2. How does the Pythagorean theorem apply to the sides of a rectangle?
  3. What are some examples of real-life objects that can be modeled as inscribed shapes in circles?
  4. How would the answer change if the diagonal was a different multiple of the shorter side?
  5. Can a square be inscribed in a circle, and if so, what would its properties be?

Tip: Always ensure that relationships like those between the diagonal and sides of a shape are checked carefully to avoid errors in geometric problems.

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagorean Theorem
Inscribed Shapes

Formulas

Area of rectangle: A = ab
Pythagorean theorem: d^2 = a^2 + b^2
Diagonal relation: d = 2a

Theorems

Pythagorean Theorem
Properties of an Inscribed Rectangle

Suitable Grade Level

Grades 9-12