Solve for xx. Express your answer in simplest radical form if necessary. x, squared, equals, 144 x 2

The equation given is:

$x^2 = 144$

To solve for $x$, we take the square root of both sides of the equation:

$x = \pm \sqrt{144}$

Since the square root of 144 is 12, this simplifies to:

$x = \pm 12$

So, the solutions for $x$ are:

$x = 12 \quad \text{and} \quad x = -12$

Would you like further details or have any questions about this solution?

Here are 5 related questions for further exploration:

1. What is the square root of other perfect squares, like 81 or 196?
2. How do you solve an equation like $x^2 = 49$?
3. How do you handle equations where the number under the square root is not a perfect square, like $x^2 = 50$?
4. What happens if the equation is $x^2 = -144$?
5. How do you simplify expressions like $\sqrt{72}$?

Tip: Remember that taking the square root of a positive number yields both a positive and a negative solution.