Solve for xx. Express your answer in simplest radical form if necessary.
x, squared, equals, 144
x
2
=
144

The equation given is:

\[
x^2 = 144
\]

To solve for \( x \), we take the square root of both sides of the equation:

\[
x = \pm \sqrt{144}
\]

Since the square root of 144 is 12, this simplifies to:

\[
x = \pm 12
\]

So, the solutions for \( x \) are:

\[
x = 12 \quad \text{and} \quad x = -12
\]

Would you like further details or have any questions about this solution?

Here are 5 related questions for further exploration:
1. What is the square root of other perfect squares, like 81 or 196?
2. How do you solve an equation like \( x^2 = 49 \)?
3. How do you handle equations where the number under the square root is not a perfect square, like \( x^2 = 50 \)?
4. What happens if the equation is \( x^2 = -144 \)?
5. How do you simplify expressions like \( \sqrt{72} \)?

**Tip:** Remember that taking the square root of a positive number yields both a positive and a negative solution.

Solve for x. Express your answer in simplest radical form if necessary. x^2 = 144

Learn how to solve the equation x^2 = 144 by taking the square root of both sides. This solution explores key algebra concepts like square roots and the properties of quadratic equations. Suitable for students in Grades 6-8.

Math Problem Statement

Solve for xx. Express your answer in simplest radical form if necessary. x, squared, equals, 144 x 2

Solution

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