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The given equation is \( v^2 = 144 \).

To solve this equation using the square root property, we follow these steps:

1. Take the square root of both sides of the equation:
   \[
   v = \pm \sqrt{144}
   \]

2. Simplify the square root:
   \[
   v = \pm 12
   \]

Thus, the two possible solutions for \( v \) are \( 12 \) and \( -12 \).

Do you want more details or have any questions? Here are five related questions you might find useful:

1. What if the equation had been \( v^2 = 169 \)? What would the solutions be?
2. How do you solve equations like \( (v + 2)^2 = 49 \)?
3. What is the difference between using the square root and factoring for solving quadratic equations?
4. What happens if the square root leads to an irrational number, like \( v^2 = 50 \)?
5. Can you explain how imaginary numbers come into play if \( v^2 \) equals a negative number?

**Tip:** Always remember that when taking the square root of a variable squared, there are two possible values: the positive and negative roots.

Solve the equation by using the square root property: v^2 = 144. Express your answers in simplified form using integers, fractions, or radicals.

Learn how to solve the quadratic equation v^2 = 144 using the square root property. This solution demonstrates key algebraic concepts and simplifies the equation step-by-step. Suitable for students in Grades 8-10.

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