The given equation is $v^2 = 144$.

To solve this equation using the square root property, we follow these steps:

1. Take the square root of both sides of the equation: $v = \pm \sqrt{144}$

2. Simplify the square root: $v = \pm 12$

Thus, the two possible solutions for $v$ are $12$ and $-12$.

Do you want more details or have any questions? Here are five related questions you might find useful:

1. What if the equation had been $v^2 = 169$? What would the solutions be?
2. How do you solve equations like $(v + 2)^2 = 49$?
3. What is the difference between using the square root and factoring for solving quadratic equations?
4. What happens if the square root leads to an irrational number, like $v^2 = 50$?
5. Can you explain how imaginary numbers come into play if $v^2$ equals a negative number?

Tip: Always remember that when taking the square root of a variable squared, there are two possible values: the positive and negative roots.