Solve for xx. Express your answer in simplest radical form if necessary. x, squared, equals, 144 x 2

The equation given is:

$x^2 = 144$

To solve for $x$, take the square root of both sides:

$x = \pm \sqrt{144}$

Since $\sqrt{144} = 12$, the solution is:

$x = \pm 12$

So the values of $x$ are $x = 12$ and $x = -12$.

Would you like more details or have any questions?

Here are 5 related questions to explore:

1. What happens if the equation is $x^2 = -144$?
2. How do you solve $x^2 = 169$?
3. What are the square roots of non-perfect squares, like $x^2 = 50$?
4. How do you solve $(x + 2)^2 = 144$?
5. Can a square root ever be negative?

Tip: Always remember that solving $x^2 = a$ results in two values, $\pm \sqrt{a}$, unless $a$ is negative.