Math Problem Statement

One root of the equation 4x2 + bx + c = 0 is 0.5. The other is equal to c. Find the values of b and c.

Solution

We know that one root of the quadratic equation

4x2+bx+c=04x^2 + bx + c = 0

is x=0.5x = 0.5 and the other root is equal to cc.

Step 1: Sum and Product of Roots

For a quadratic equation of the form ax2+bx+c=0ax^2 + bx + c = 0, if the roots are r1r_1 and r2r_2, then:

  1. The sum of the roots is r1+r2=bar_1 + r_2 = -\frac{b}{a}.
  2. The product of the roots is r1r2=car_1 \cdot r_2 = \frac{c}{a}.

In this problem:

  • a=4a = 4
  • r1=0.5r_1 = 0.5
  • r2=cr_2 = c

Step 2: Using the Sum of the Roots

Since r1+r2=b4r_1 + r_2 = -\frac{b}{4}, we have:

0.5+c=b40.5 + c = -\frac{b}{4}

This gives us the equation:

b=4(0.5+c)=24cb = -4(0.5 + c) = -2 - 4c

Step 3: Using the Product of the Roots

The product of the roots r1r2=c4r_1 \cdot r_2 = \frac{c}{4}:

0.5c=c40.5 \cdot c = \frac{c}{4}

Solving this equation:

0.5c=c40.5c = \frac{c}{4}

Multiplying both sides by 4 to clear the fraction:

2c=c2c = c

This implies c=0c = 0.

Step 4: Substitute c=0c = 0 to Find bb

Substituting c=0c = 0 into our equation for bb:

b=24(0)=2b = -2 - 4(0) = -2

Conclusion

The values of bb and cc are: b=2,c=0b = -2, \quad c = 0

Would you like further details or have any questions?

  1. How do you find the roots of a quadratic equation?
  2. What if one of the roots was different? How would it change the solution?
  3. How can you solve a quadratic equation without knowing any roots?
  4. What are the applications of finding roots in real-world problems?
  5. How does the quadratic formula relate to this method?

Tip: In quadratic equations, if one root is known, the sum and product of roots are powerful tools to find the other values.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Sum and Product of Roots

Formulas

Quadratic equation: ax^2 + bx + c = 0
Sum of roots: r1 + r2 = -b/a
Product of roots: r1 * r2 = c/a

Theorems

Sum and Product of Roots Theorem

Suitable Grade Level

Grades 9-10