Math Problem Statement

Given two quadratic equations: -x^2 + 4x + 5 and 2x^2 - 6x - 5, find a, b, and c; determine the roots of the equations; find the axis of symmetry; and use it to find the vertex.

Solution

The image contains two quadratic equations with tasks asking for identifying aa, bb, and cc; finding the roots, the axis of symmetry, and the vertex.

Let us analyze and solve the equations step by step:


7. Given: x2+4x+5-x^2 + 4x + 5

  1. Identify aa, bb, and cc:

    • The equation is in the form ax2+bx+cax^2 + bx + c.
    • Here, a=1a = -1, b=4b = 4, c=5c = 5.
  2. Find the roots (solutions to ax2+bx+c=0ax^2 + bx + c = 0): Use the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} Substituting: [ x = \frac{-4 \pm \sqrt{4^2 - 4(-1)(5)}}{2

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Vertex Form
Axis of Symmetry

Formulas

Quadratic Formula: x = (-b ± √(b^2 - 4ac)) / 2a
Axis of Symmetry: x = -b / 2a
Vertex (y-value): Substitute x = -b / 2a into the equation y = ax^2 + bx + c

Theorems

Quadratic Formula

Suitable Grade Level

Grades 8-10