Let's solve this step-by-step by setting up the appropriate equations based on the information given.

Step-by-step Solution:

1. Increase $x$ by 30%:

   • Increasing $x$ by 30% means the new value after the increase is $x + 0.30x = 1.30x$.

2. Decrease the new value by 20%:

   • Decreasing this new value by 20% means the value becomes $1.30x - 0.20 \times 1.30x = 1.30x \times 0.80 = 1.04x$.

3. Resulting value is 24% more than the original value:

   • The problem states that this resulting value is 24% more than the original value $x$.
   • This means $1.04x = x + 0.24x = 1.24x$.

4. Set up the equation:

   • We have two expressions for the resulting value after both percentage changes: $1.04x = 1.24x$

5. Solving for $x$:

   • To solve for $x$, notice that we have an equation that shows a contradiction if it states $1.04x = 1.24x$. This suggests a misunderstanding in the setup of our understanding:

6. Correcting the interpretation:

   • Let's reconsider: After applying both percentage changes, $1.04x$ is the modified $x$ value after operations, equating it to 1.24 times the initial value is already done as above. Which implies the initial value of $x$ is self-resolving in that case:

   • By isolating $x$, knowing it matches the manipulative outcome:

     $x = x \times \frac{1.04}{1.24}$

   • Here, let's re-isolate to solve for equivalence identity:

     $\frac{1.04x}{1.24x} = 1$

   This confirms a setup implying equality:

   $x = \frac{1.04}{1.24} x = x$

Conclusion:

Since we are not calculating $x$ against an unknown value or variable driven difference: The original and resulting values represent a dynamic process reflecting the very variable itself as unchanged due to its own percentage operations effectively canceling one another in unique combinatory approach and outcome. Thus, effectively, any value of $x$ remains, yielding constant original $x$ irrespective of transformation operations.

Hence, the solution demonstrates that $x$ would not change but illustrates via transformations without adding external result deviations: Thus: Any valid real number x holds equivalence.

Would you like further clarification or explore more challenging examples or exercises around percentage changes, and equations?

Here are some follow-up questions for additional practice:

1. What happens if instead, $x$ is decreased by 30% first and then increased by 40%?
2. If the original value of $x$ is 100, what is the resulting value after the same changes?
3. How would the result change if the value was increased by 50% first and then decreased by 30%?
4. Can you derive a general formula for successive percentage increases and decreases?
5. What is the result if $x$ is first increased by 20%, then increased again by 20%, instead of a decrease?

Tip: When working with percentages in equations, it's crucial to translate percentage changes into decimal multipliers to manage the arithmetic easily.