Math Problem Statement
Solution
Let's solve this problem step by step.
Problem Breakdown:
- The price of the article increases by and then decreases by , leading to a drop in price by Rs. 180.
- After one more iteration (increase by and then decrease by ), the price falls further by Rs. 160.
- We need to find the original price of the article.
Key Concept:
When the price is increased by and then decreased by , the net effect on the price is a decrease, as the percentage decrease applies to the increased price. The formula for the new price after an increase and then decrease of is: where is the price before the operation.
Let the original price be , and the change factor be: After the first iteration: The difference after the first iteration is:
After the second iteration: The difference after the second iteration is:
System of Equations:
We now have two equations:
We can solve these two equations simultaneously to find (the original price) and . Let's solve this now.The solution to the system of equations gives us the original price of the article, rupees, and the change factor .
Thus, the original price of the article is Rs. 1620.
Would you like more details or have any further questions? Here are 5 related questions for practice:
- How does the percentage increase and decrease lead to an overall price drop?
- What is the impact on the final price if the increase and decrease percentages are different?
- If the owner repeated this process three times, what would be the price reduction?
- Can you find the percentage that caused the drop in price?
- What is the total percentage drop in price after two iterations?
Tip: When prices are increased and then decreased by the same percentage, the overall effect is always a decrease. The percentage loss is quadratic, not linear.
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Math Problem Analysis
Mathematical Concepts
Algebra
Simultaneous Equations
Percentage Increase and Decrease
Formulas
New Price = P × (1 - x² / 100²)
P₀(1 - k) = 180
P₀k(1 - k) = 160
Theorems
-
Suitable Grade Level
Grade 10-12
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