Math Problem Statement

²log 8 = 3 <=>

Solution

To solve the equation 2log8=32 \log 8 = 3, let's break it down step-by-step:

  1. Divide both sides by 2 to isolate the logarithmic term: log8=32\log 8 = \frac{3}{2}

  2. This equation means: log108=32\log_{10} 8 = \frac{3}{2}, assuming it's a common logarithm (base 10).

  3. Now, recall that log108=x\log_{10} 8 = x implies 10x=810^x = 8.

    So, 1032=810^{\frac{3}{2}} = 8.

  4. Simplify 103210^{\frac{3}{2}}: 1032=103=100010^{\frac{3}{2}} = \sqrt{10^3} = \sqrt{1000}

    This gives approximately 1000=31.62\sqrt{1000} = 31.62.

  5. Therefore, 31.62831.62 \approx 8 is false.

Hence, the equation is only valid if it's interpreted in a different logarithmic base, specifically base 2.

Would you like more details, or do you have questions? Here are some related questions for practice:

  1. What is the value of log28\log_2 8?
  2. How do you convert logarithms of different bases?
  3. What does log101000\log_{10} 1000 equal?
  4. Solve 3log5=63 \log 5 = 6 for log5\log 5.
  5. What is the general form of a logarithmic equation?

Tip: When working with logarithms, always verify the base being used (common or natural logarithm).

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Math Problem Analysis

Mathematical Concepts

Logarithms
Logarithmic Equations
Bases of Logarithms

Formulas

log_b x = y <=> b^y = x
log_b (xy) = log_b x + log_b y
log_b (x^y) = y * log_b x

Theorems

Change of Base Formula
Properties of Logarithms

Suitable Grade Level

Grades 9-11