Math Problem Statement

Solve each equation for y: x - 3(y + 2) = 6

Solution

The equation in the image is:

x3(y+2)=6x - 3(y + 2) = 6

We are asked to solve for yy. Let's go through the steps:

Step 1: Expand the equation

Distribute the 3-3 to both yy and 22: x3y6=6x - 3y - 6 = 6

Step 2: Isolate the yy-term

Add 6 to both sides to isolate the yy-term: x3y=12x - 3y = 12

Step 3: Solve for yy

Subtract xx from both sides: 3y=12x-3y = 12 - x

Now, divide both sides by 3-3: y=x123y = \frac{x - 12}{3}

Thus, the solution for yy is: y=x123y = \frac{x - 12}{3}

Would you like further clarification or more details on any step?

Here are 5 related questions to consider:

  1. How would the solution change if the constant on the right-hand side was different?
  2. What happens if there are multiple variables in the equation?
  3. Can this equation be solved graphically? How would you plot it?
  4. How do you verify if the solution is correct by plugging back values for xx?
  5. What if you were solving for xx instead of yy?

Tip: Always perform distribution carefully to avoid mistakes when handling parentheses.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Algebraic Manipulation

Formulas

Distribution: a(b + c) = ab + ac
Isolating a variable: ax + b = c => x = (c - b)/a

Theorems

Basic Algebraic Operations

Suitable Grade Level

Grades 7-9