To solve the equation $3(x + 2) = y - 6$ for $y$, we need to isolate $y$ on one side of the equation. Here are the steps:

1. Expand the left side of the equation:

$3(x + 2) = y - 6$

$3x + 6 = y - 6$

2. Add 6 to both sides to move the constant term on the right side to the left:

$3x + 6 + 6 = y - 6 + 6$

$3x + 12 = y$

3. Rewrite the equation with $y$ isolated:

$y = 3x + 12$

Thus, the solution for $y$ is:

$\boxed{y = 3x + 12}$

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