https://file.aiquickdraw.com/mathbot/file/1725855549805327cwoqv.jpg

I see the image contains three algebraic equations. Let me list and solve each one for you:

### Equation 1:
\[
2x + 8 = 20
\]

**Steps to solve:**
1. Subtract 8 from both sides:
   \[
   2x = 20 - 8 \implies 2x = 12
   \]
2. Divide by 2:
   \[
   x = \frac{12}{2} \implies x = 6
   \]

### Equation 2:
\[
\frac{3}{2}x + 5 = 14
\]

**Steps to solve:**
1. Subtract 5 from both sides:
   \[
   \frac{3}{2}x = 14 - 5 \implies \frac{3}{2}x = 9
   \]
2. Multiply both sides by the reciprocal of \(\frac{3}{2}\) (which is \(\frac{2}{3}\)):
   \[
   x = 9 \times \frac{2}{3} \implies x = 6
   \]

### Equation 3:
\[
\frac{x - 9}{-4} = 7
\]

**Steps to solve:**
1. Multiply both sides by \(-4\) to eliminate the denominator:
   \[
   x - 9 = 7 \times (-4) \implies x - 9 = -28
   \]
2. Add 9 to both sides:
   \[
   x = -28 + 9 \implies x = -19
   \]

### Summary of Solutions:
1. \(x = 6\)
2. \(x = 6\)
3. \(x = -19\)

Would you like more details or further clarification?

Here are 5 related questions:
1. How do you solve equations with fractions?
2. What is the method to solve equations with variables on both sides?
3. How do you deal with negative coefficients in equations?
4. How does multiplying both sides of an equation affect the solution?
5. Can we apply the same approach for solving systems of equations?

**Tip:** Always check your solution by substituting the value of \(x\) back into the original equation to verify correctness.

Solve the following algebraic equations:
1. 2x + 8 = 20
2. (3/2)x + 5 = 14
3. (x - 9)/(-4) = 7

Learn how to solve three linear equations, including those with fractions and negative denominators. This step-by-step solution is suitable for students in Grades 7-9 and covers key algebraic methods.

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