Let's solve the given equations:

(a) $\frac{5x}{3} - 6 = 4$

1. Start by isolating the term involving $x$ on one side: $\frac{5x}{3} = 4 + 6$ $\frac{5x}{3} = 10$

2. Multiply both sides by 3 to eliminate the fraction: $5x = 10 \times 3$ $5x = 30$

3. Divide both sides by 5 to solve for $x$: $x = \frac{30}{5}$ $x = 6$

(b) $5x + 10 = 2x - 14$

1. Start by getting all the $x$ terms on one side of the equation: $5x - 2x = -14 - 10$ $3x = -24$

2. Divide both sides by 3 to solve for $x$: $x = \frac{-24}{3}$ $x = -8$

Final Solutions:

• For (a), $x = 6$.
• For (b), $x = -8$.

Would you like further details on these solutions or have any other questions?

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Here are 8 related questions:

1. How do you solve an equation involving fractions?
2. What happens if you have to solve an equation with variables on both sides?
3. How can you check if your solution to an equation is correct?
4. What are the steps to solving multi-step linear equations?
5. How do you isolate a variable in an equation?
6. What is the importance of the order of operations in solving equations?
7. How do you handle equations with negative coefficients?
8. Can you solve equations involving square roots or exponents?

Tip: Always verify your solution by substituting it back into the original equation to ensure it satisfies the equation.