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I see you've uploaded an image containing several equations. Let's go through them step by step.

### (i) Solve: 
\[
17 - 28 = k + 5
\]
First, simplify the left-hand side:
\[
17 - 28 = -11
\]
Now we have:
\[
-11 = k + 5
\]
To solve for \(k\), subtract 5 from both sides:
\[
k = -11 - 5 = -16
\]
So, \(k = -16\).

---

### (j) Solve: 
\[
\frac{5m}{4} = -15
\]
First, multiply both sides by 4 to get rid of the fraction:
\[
5m = -15 \times 4 = -60
\]
Now divide both sides by 5:
\[
m = \frac{-60}{5} = -12
\]
So, \(m = -12\).

---

### (k) Solve: 
\[
\frac{m - 6}{2} = 4
\]
Multiply both sides by 2:
\[
m - 6 = 4 \times 2 = 8
\]
Now, add 6 to both sides:
\[
m = 8 + 6 = 14
\]
So, \(m = 14\).

---

### (l) Solve: 
\[
\frac{k}{5} - 10 = 2
\]
First, add 10 to both sides:
\[
\frac{k}{5} = 2 + 10 = 12
\]
Now, multiply both sides by 5:
\[
k = 12 \times 5 = 60
\]
So, \(k = 60\).

---

### (m) Solve: 
\[
4 + \frac{h}{5} = 6
\]
First, subtract 4 from both sides:
\[
\frac{h}{5} = 6 - 4 = 2
\]
Now, multiply both sides by 5:
\[
h = 2 \times 5 = 10
\]
So, \(h = 10\).

---

### (n) Solve: 
\[
2(x + 2) = 6
\]
First, divide both sides by 2:
\[
x + 2 = \frac{6}{2} = 3
\]
Now, subtract 2 from both sides:
\[
x = 3 - 2 = 1
\]
So, \(x = 1\).

---

### (o) Solve: 
\[
-(d + 3) = 11
\]
First, multiply both sides by -1:
\[
d + 3 = -11
\]
Now, subtract 3 from both sides:
\[
d = -11 - 3 = -14
\]
So, \(d = -14\).

---

Would you like any further explanation or details on any step? Here are some related questions:

1. Can you explain how to solve linear equations step-by-step?
2. How would these problems change if they involved fractions or decimals?
3. What happens if variables appear on both sides of an equation?
4. How would you solve an equation with two variables?
5. What are common mistakes to avoid when solving linear equations?

**Tip:** Always check your solution by substituting the value back into the original equation to see if both sides are equal!

Solve the following equations: (i) 17 - 28 = k + 5, (j) (5m/4) = -15, (k) (m - 6)/2 = 4, (l) k/5 - 10 = 2, (m) 4 + h/5 = 6, (n) 2(x + 2) = 6, (o) -(d + 3) = 11

Learn how to solve a series of linear equations, including equations with fractions and negative numbers. This guide provides a detailed solution for each equation, covering key algebraic techniques such as isolating variables and simplifying expressions. Suitable for students in Grades 6-8.

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