Math Problem Statement

Solve this question with solution

Solve the following equations and verify the solutions: 1. x + 7 = 17/6 - 5x/6 2. y - (y - 5)/2 = 1 - 2y 3. 15(x - 4) - 2(x - 9) = 2(x - 1) 4. (m - 2)/3 + 1 = 2m/7 5. (a + 2)/4 + (a - 3)/5 = (3a - 5)/8 6. (3x - 1)/4 - (2x + 2)/6 = 5/2 - 2x

Solution

Let's work through each equation step by step.

Equation 1:

x+7=1765x6x + 7 = \frac{17}{6} - \frac{5x}{6}

  1. Multiply through by 6 to eliminate fractions: 6(x+7)=175x6(x + 7) = 17 - 5x 6x+42=175x6x + 42 = 17 - 5x

  2. Add 5x5x to both sides: 11x+42=1711x + 42 = 17

  3. Subtract 42 from both sides: 11x=174211x = 17 - 42 11x=2511x = -25

  4. Divide by 11: x=2511x = -\frac{25}{11}

Equation 2:

yy52=12yy - \frac{y - 5}{2} = 1 - 2y

  1. Multiply through by 2 to eliminate fractions: 2y(y5)=2(12y)2y - (y - 5) = 2(1 - 2y) 2yy+5=24y2y - y + 5 = 2 - 4y

  2. Simplify: y+5=24yy + 5 = 2 - 4y

  3. Add 4y4y to both sides: 5y+5=25y + 5 = 2

  4. Subtract 5 from both sides: 5y=255y = 2 - 5 5y=35y = -3

  5. Divide by 5: y=35y = -\frac{3}{5}

Equation 3:

15(x4)2(x9)=2(x1)15(x - 4) - 2(x - 9) = 2(x - 1)

  1. Expand the brackets: 15x602x+18=2x215x - 60 - 2x + 18 = 2x - 2 13x42=2x213x - 42 = 2x - 2

  2. Subtract 2x2x from both sides: 11x42=211x - 42 = -2

  3. Add 42 to both sides: 11x=4011x = 40

  4. Divide by 11: x=4011x = \frac{40}{11}

Equation 4:

m23+1=2m7\frac{m - 2}{3} + 1 = \frac{2m}{7}

  1. Multiply through by 21 to eliminate fractions: 7(m2)+21=3(2m)7(m - 2) + 21 = 3(2m) 7m14+21=6m7m - 14 + 21 = 6m

  2. Simplify: 7m+7=6m7m + 7 = 6m

  3. Subtract 6m6m from both sides: m+7=0m + 7 = 0

  4. Subtract 7 from both sides: m=7m = -7

Equation 5:

a+24+a35=3a58\frac{a + 2}{4} + \frac{a - 3}{5} = \frac{3a - 5}{8}

  1. Find the least common denominator (LCD) which is 40, and multiply through: 40(a+24)+40(a35)=40(3a58)40 \left( \frac{a + 2}{4} \right) + 40 \left( \frac{a - 3}{5} \right) = 40 \left( \frac{3a - 5}{8} \right) 10(a+2)+8(a3)=5(3a5)10(a + 2) + 8(a - 3) = 5(3a - 5)

  2. Expand the brackets: 10a+20+8a24=15a2510a + 20 + 8a - 24 = 15a - 25 18a4=15a2518a - 4 = 15a - 25

  3. Subtract 15a15a from both sides: 3a4=253a - 4 = -25

  4. Add 4 to both sides: 3a=213a = -21

  5. Divide by 3: a=7a = -7

Equation 6:

3x142x+26=522x\frac{3x - 1}{4} - \frac{2x + 2}{6} = \frac{5}{2} - 2x

  1. Find the least common denominator, which is 12, and multiply through: 12(3x14)12(2x+26)=12(52)12(2x)12 \left( \frac{3x - 1}{4} \right) - 12 \left( \frac{2x + 2}{6} \right) = 12 \left( \frac{5}{2} \right) - 12(2x) 3(3x1)2(2x+2)=6(5)24x3(3x - 1) - 2(2x + 2) = 6(5) - 24x

  2. Expand the brackets: 9x34x4=3024x9x - 3 - 4x - 4 = 30 - 24x 5x7=3024x5x - 7 = 30 - 24x

  3. Add 24x24x to both sides: 29x7=3029x - 7 = 30

  4. Add 7 to both sides: 29x=3729x = 37

  5. Divide by 29: x=3729x = \frac{37}{29}


Would you like further details on any of these solutions or verification steps?

Here are 5 related questions for practice:

  1. How can you solve equations with more complex fractions?
  2. What is the best approach to handle equations with variables on both sides?
  3. How do you verify the solution of an equation after solving it?
  4. How does clearing fractions help simplify equations?
  5. Can you solve quadratic equations using a similar approach?

Tip: Always double-check for common denominators when dealing with fractions to simplify calculations!

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Math Problem Analysis

Mathematical Concepts

Solving linear equations
Working with fractions
Simplifying algebraic expressions

Formulas

Basic equation solving (isolating variables)
Finding common denominators in fractions

Theorems

Properties of equality

Suitable Grade Level

Grade 9