https://file.aiquickdraw.com/mathbot/file/1725387572665uj7a6z3e.jpg

The equation given in the image is:

\[
12x + \frac{6}{11} - 5 = 0
\]

To solve for \(x\), follow these steps:

1. Combine like terms:
   \[
   12x + \frac{6}{11} - 5 = 0
   \]
   Move the constants to the other side of the equation:
   \[
   12x = 5 - \frac{6}{11}
   \]

2. To combine the constants on the right-hand side, convert 5 into a fraction with a denominator of 11:
   \[
   5 = \frac{55}{11}
   \]
   Now subtract the fractions:
   \[
   \frac{55}{11} - \frac{6}{11} = \frac{49}{11}
   \]
   So,
   \[
   12x = \frac{49}{11}
   \]

3. Solve for \(x\) by dividing both sides by 12:
   \[
   x = \frac{49}{11} \times \frac{1}{12} = \frac{49}{132}
   \]

So, the solution is:
\[
x = \frac{49}{132}
\]

Would you like more details on this solution or have any other questions?

---

Here are some follow-up questions to deepen your understanding:

1. How can you verify the solution \( x = \frac{49}{132} \) by substituting it back into the original equation?
2. What steps would you take if the equation had a variable in the denominator?
3. How would you solve the equation if there was an additional term with \( x \) on the right side?
4. Can you think of a different approach to solve the equation, such as using decimal approximations?
5. How would the solution process change if the equation included square roots or higher powers of \( x \)?

**Tip:** When solving equations with fractions, it's often helpful to find a common denominator early on to simplify your calculations.

Solve the following equation for x: 12x + 6/11 - 5 = 0

Learn how to solve linear equations involving fractions with this step-by-step guide. This example, 12x + 6/11 - 5 = 0, teaches you how to handle fraction operations and solve for x, making it ideal for students in Grades 6-8.

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