Let's solve the two equations:

a)

$\frac{3x + 4}{2} = 9.5$ To solve for $x$, follow these steps:

1. Multiply both sides of the equation by 2 to eliminate the denominator: $3x + 4 = 9.5 \times 2$ $3x + 4 = 19$
2. Subtract 4 from both sides: $3x = 19 - 4$ $3x = 15$
3. Divide both sides by 3: $x = \frac{15}{3} = 5$ Thus, the solution is $x = 5$.

b)

$\frac{7 + 2x}{3} = 5$ To solve for $x$, follow these steps:

1. Multiply both sides of the equation by 3 to eliminate the denominator: $7 + 2x = 5 \times 3$ $7 + 2x = 15$
2. Subtract 7 from both sides: $2x = 15 - 7$ $2x = 8$
3. Divide both sides by 2: $x = \frac{8}{2} = 4$ Thus, the solution is $x = 4$.

Summary of solutions:

• a) $x = 5$
• b) $x = 4$

Would you like further explanations or have any questions about these steps?

Here are some related questions for practice:

1. Solve $\frac{2x - 1}{3} = 6$.
2. Solve $\frac{4x + 5}{2} = 8$.
3. If $\frac{3x + 2}{4} = 7$, what is $x$?
4. Solve for $x$ in $\frac{5x - 7}{5} = 2$.
5. Solve for $x$ in $\frac{6x + 1}{3} = 10$.

Tip: Always eliminate the denominator first by multiplying both sides by the denominator to simplify the equation.