Math Problem Statement

Solve each of the following equations. Make sure to check your solutions. (3x-2)/5+x+4/3=14(x+1)/15

Solution

Let's solve the equation step by step:

Given Equation:

3x25+x+43=14(x+1)15\frac{3x - 2}{5} + x + \frac{4}{3} = \frac{14(x + 1)}{15}

Step 1: Eliminate the fractions by multiplying by the Least Common Denominator (LCD).

The LCD of 5, 3, and 15 is 15. Multiply the entire equation by 15 to eliminate the fractions:

15(3x25+x+43)=15×14(x+1)1515 \left( \frac{3x - 2}{5} + x + \frac{4}{3} \right) = 15 \times \frac{14(x + 1)}{15}

This gives: [ 15 \times \frac

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Rational Expressions

Formulas

Elimination of fractions by multiplying by the Least Common Denominator (LCD)
Simplification of expressions

Theorems

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Suitable Grade Level

Grades 8-10