The problem you uploaded can be broken down as follows:

We have three pieces of information:

1. A customer pays $25 for 2 pizzas delivered.
2. Another customer pays $58 for 5 pizzas delivered.
3. We need to determine how many pizzas a customer receives if they pay $80.

Step 1: Set up equations for both customers.

Let $p$ be the cost per pizza, and $d$ be the delivery fee. For each situation:

• For the first customer:
  $2p + d = 25$

• For the second customer: $5p + d = 58$

Step 2: Solve for $p$ and $d$.

Subtract the first equation from the second:

$(5p + d) - (2p + d) = 58 - 25$ $3p = 33$ $p = 11$

Now substitute $p = 11$ into the first equation: $2(11) + d = 25$ $22 + d = 25$ $d = 3$

Step 3: Calculate for the $80 payment.

Now that we know the cost per pizza is $11 and the delivery fee is $3, set up the equation for a customer who pays $80: $xp + d = 80$ Substitute $p = 11$ and $d = 3$: $11x + 3 = 80$ $11x = 77$ $x = 7$

Answer:

The customer who pays $80 gets 7 pizzas.

Do you want more details on any part of this solution or have any questions?

Here are some related questions for further practice:

1. If a customer paid $100, how many pizzas would they get?
2. What would the total cost be for 8 pizzas delivered?
3. If the delivery fee were increased to $5, how would that affect the number of pizzas a customer gets for $80?
4. How much would 3 pizzas cost without the delivery fee?
5. How would the equations change if the price per pizza were different for different customers?

Tip: When you have two variables, solving systems of equations is a great strategy!