We can set up a system of equations to solve for the price of a pizza and the delivery fee.

Define Variables:

• Let $p$ be the price of one pizza.
• Let $d$ be the delivery fee.

Given Information:

1. A customer pays $25 for 2 pizzas:
   $2p + d = 25$
2. Another customer pays $58 for 5 pizzas:
   $5p + d = 58$

Solve for $p$ and $d$:

Step 1: Subtract the first equation from the second:

$(5p + d) - (2p + d) = 58 - 25$ $3p = 33$ $p = 11$

Step 2: Solve for $d$:

Substituting $p = 11$ into the first equation: $2(11) + d = 25$ $22 + d = 25$ $d = 3$

Step 3: Find the Number of Pizzas for $80:

Using the equation: $xp + d = 80$ $x(11) + 3 = 80$ $11x = 77$ $x = 7$

Thus, a customer who pays $80 receives 7 pizzas.

Would you like more details or have any questions?

Related Questions:

1. What would be the cost for 10 pizzas, including delivery?
2. If the restaurant removes the delivery fee, how much would each customer pay per pizza?
3. What if the delivery fee increased to $5? How would that affect the cost?
4. Can you create a general formula for the cost of $x$ pizzas with a delivery fee?
5. If a customer has $100, how many pizzas can they order?

Math Tip:

When solving systems of equations, elimination is a powerful method when the coefficients of one variable are the same or can be made the same.