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Let's define the variables:

- Let \( s \) be the cost of a small pizza.
- Let \( m \) be the cost of a medium pizza.
- Let \( l \) be the cost of a large pizza.

Based on the given information, we can set up the following equations from each package:

1. **Small Gathering Package:**
   \[
   s + m + l = 28
   \]

2. **Family Reunion Package:**
   \[
   4s + 2m + l = 58
   \]

3. **Huge Party Package:**
   \[
   6s + 5m + 4l = 135
   \]

We now have a system of three equations:
1. \( s + m + l = 28 \)
2. \( 4s + 2m + l = 58 \)
3. \( 6s + 5m + 4l = 135 \)

### Step 1: Eliminate \( l \)
Let's subtract the first equation from the second to eliminate \( l \):
\[
(4s + 2m + l) - (s + m + l) = 58 - 28
\]
\[
3s + m = 30
\]

This gives us a new equation:
\[
3s + m = 30
\]

### Step 2: Create another equation without \( l \)
Next, we subtract the first equation from the third:
\[
(6s + 5m + 4l) - (s + m + l) = 135 - 28
\]
\[
5s + 4m + 3l = 107

A pizza store offers three different party packages of pizzas. The packages and prices are listed below. If pizzas cost the same individually or in a package, what is the cost of a large pizza?

Find the cost of a large pizza using algebra and systems of equations based on a pizza store's party packages. This problem covers essential algebraic skills and elimination techniques, suitable for Grades 8-10.

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