The weight of meteorite A is 3 times the weight of meteorite B. If the sum of their weights is 80 ​tons, find the weight of each.


Let's denote the weight of meteorite B as \( x \) tons. Since meteorite A weighs 3 times as much as meteorite B, the weight of meteorite A would be \( 3x \) tons.

Given that the sum of their weights is 80 tons, we can write the equation:

\[
x + 3x = 80
\]

Combine like terms:

\[
4x = 80
\]

Now, solve for \( x \):

\[
x = \frac{80}{4} = 20
\]

So, the weight of meteorite B is 20 tons.

Since meteorite A weighs 3 times as much as meteorite B, the weight of meteorite A is:

\[
3x = 3 \times 20 = 60 \text{ tons}
\]

**Answer:**
- The weight of meteorite A is 60 tons.
- The weight of meteorite B is 20 tons.

Would you like any further details or have any questions about this problem?

Here are 5 related questions:
1. If the weight of meteorite A was 4 times the weight of meteorite B, what would their respective weights be if the total was 80 tons?
2. How would the solution change if the total weight was 100 tons instead of 80 tons?
3. If meteorite B weighed 10 tons less, how much would meteorite A weigh?
4. What is the weight difference between meteorite A and meteorite B?
5. If the weights of both meteorites were doubled, what would be the new total weight?

**Tip:** When solving word problems, it's helpful to define variables clearly and write down the equation that models the problem. This step makes it easier to solve the problem systematically.

The weight of meteorite A is 3 times the weight of meteorite B. If the sum of their weights is 80 ​tons, find the weight of each.

Learn how to solve a linear equation involving the weights of two meteorites, where one is three times heavier than the other, and their combined weight is 80 tons. This problem highlights fundamental algebraic concepts and equation-solving skills, suitable for students in Grades 6-8.

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