Shrey's mass 8kg more than thrice shiv's mass. If her mass is 50kg ,find shiv's mass

Let's denote Shiv's mass as \( x \) kg.

According to the problem, Shrey's mass is 8 kg more than three times Shiv's mass. Therefore, we can set up the equation:

\[
3x + 8 = 50
\]

To find Shiv's mass, solve the equation for \( x \):

1. Subtract 8 from both sides:

\[
3x = 50 - 8
\]

\[
3x = 42
\]

2. Divide both sides by 3:

\[
x = \frac{42}{3}
\]

\[
x = 14
\]

So, Shiv's mass is 14 kg.

Would you like any further details or have any questions? Here are some related problems:

1. If Shrey's mass was 60 kg, what would Shiv's mass be?
2. How would the equation change if Shrey's mass was twice Shiv's mass instead?
3. If the difference between Shrey's and Shiv's masses was 20 kg, how much would Shiv weigh?
4. What would be the combined mass of Shiv and Shrey?
5. If Shiv gained 5 kg, what would be the new difference between their masses?

**Tip:** When dealing with word problems, translating the words into algebraic expressions is the key step to finding the solution.

Shrey's mass is 8 kg more than thrice Shiv's mass. If her mass is 50 kg, find Shiv's mass.

Learn how to solve a linear equation where Shrey's mass is 8 kg more than three times Shiv's mass. With a detailed step-by-step solution, this problem is suitable for students in Grades 6-8, covering essential algebraic concepts.

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