Let's solve the equation \( 5(x + 5) = 20 \).

1. **Expand the equation**:
   \[
   5x + 25 = 20
   \]

2. **Subtract 25 from both sides**:
   \[
   5x = 20 - 25
   \]
   \[
   5x = -5
   \]

3. **Divide both sides by 5**:
   \[
   x = \frac{-5}{5}
   \]
   \[
   x = -1
   \]

The solution is \( x = -1 \).

Do you want more details, or have any questions?

Here are 5 related questions:
1. What happens if you divide both sides by 5 before expanding?
2. Can you solve \( 4(x + 3) = 12 \) using similar steps?
3. How would the solution change if the equation was \( 5(x + 5) = 30 \)?
4. Can you solve \( 5(x - 5) = 20 \) instead?
5. How do you solve \( 6x + 3 = 15 \)?

**Tip**: Always try to isolate the variable by performing inverse operations step-by-step.

Learn how to solve the linear equation 5(x + 5) = 20 step-by-step. This problem involves basic algebraic concepts such as expanding and isolating variables, suitable for students in Grades 6-8. Master the use of inverse operations to find the solution x = -1.

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