https://file.aiquickdraw.com/mathbot/file/1728814894598vynv54u0.jpg

The equation in the image appears to be:

\[
5x - 20 = 3x + 10
\]

Let's solve for \(x\):

1. Subtract \(3x\) from both sides to move the variable terms to one side:
   \[
   5x - 3x - 20 = 10
   \]
   Simplifying:
   \[
   2x - 20 = 10
   \]

2. Add 20 to both sides to move the constants to the other side:
   \[
   2x = 30
   \]

3. Finally, divide both sides by 2 to solve for \(x\):
   \[
   x = 15
   \]

So, the solution is \(x = 15\).

Would you like more details on any part of this solution? Here are some related questions to expand on:

1. What happens when the variable appears on both sides of the equation?
2. How do you handle constants when solving linear equations?
3. Can you check your solution by plugging \(x = 15\) back into the original equation?
4. What would happen if the equation had no solution or infinite solutions?
5. How would you approach solving a quadratic equation instead?

**Tip:** Always check your solution by substituting it back into the original equation to ensure it's correct.

Learn how to solve the linear equation 5x - 20 = 3x + 10 step by step. This problem covers essential algebraic techniques for solving equations with variables on both sides, suitable for Grades 8-10.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation