https://file.aiquickdraw.com/mathbot/file/1726712374239hbm24d2a.jpg

The image contains two equations:

1. \( 3x - 1 = 20 \)
2. \( -5y - 4 = -29 \)

Let's solve them one by one.

### 1. Solving \( 3x - 1 = 20 \):
\[
3x - 1 = 20
\]
Add 1 to both sides:
\[
3x = 21
\]
Now, divide by 3:
\[
x = \frac{21}{3} = 7
\]

### 2. Solving \( -5y - 4 = -29 \):
\[
-5y - 4 = -29
\]
Add 4 to both sides:
\[
-5y = -25
\]
Now, divide by -5:
\[
y = \frac{-25}{-5} = 5
\]

Thus, the solutions are:
- \( x = 7 \)
- \( y = 5 \)

Would you like any more details on these steps?

Here are some related questions for further practice:
1. How do you solve linear equations with variables on both sides?
2. What happens when you have a fractional coefficient for \( x \) or \( y \)?
3. How would you solve the equations if there were decimals instead of whole numbers?
4. How can you check your solutions after solving?
5. What are some methods to solve equations with two variables?

**Tip**: Always perform the same operation on both sides of the equation to maintain balance.

Solve the equations: 3x - 1 = 20 and -5y - 4 = -29.

Learn how to solve the linear equations 3x - 1 = 20 and -5y - 4 = -29 with a step-by-step solution. This problem demonstrates key algebraic concepts for isolating variables and applying basic operations. Suitable for students in Grades 6-8.

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