Let's solve the equation \( 5(x + 4) = 20 \).

### Step-by-Step Solution:

1. **Distribute** the 5 on the left-hand side:
   \[
   5(x + 4) = 5 \cdot x + 5 \cdot 4 = 5x + 20
   \]
   So, the equation becomes:
   \[
   5x + 20 = 20
   \]

2. **Subtract 20** from both sides to eliminate the constant on the left-hand side:
   \[
   5x + 20 - 20 = 20 - 20
   \]
   Simplifying:
   \[
   5x = 0
   \]

3. **Divide both sides by 5** to solve for \(x\):
   \[
   \frac{5x}{5} = \frac{0}{5}
   \]
   So:
   \[
   x = 0
   \]

### Final Answer:
\[
x = 0
\]

Would you like further details or have any questions about this? Here are some related questions for practice:

1. Solve \( 3(x + 2) = 12 \).
2. Solve \( 2x - 7 = 9 \).
3. Solve \( 4(x - 3) = 8 \).
4. Solve \( 6x + 18 = 0 \).
5. Solve \( x + 5 = 3x - 7 \).

**Tip:** Always remember to distribute multiplication across terms in parentheses before proceeding with other steps.

Learn how to solve the linear equation 5(x+4)=20 with a detailed step-by-step solution. This problem demonstrates the distributive property and solving for x in a simple linear equation. Suitable for students in Grades 6-8.

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