Let's solve the equation \( 2y + 12 = 28 \).

### Step 1: Subtract 12 from both sides
\[
2y + 12 - 12 = 28 - 12
\]
\[
2y = 16
\]

### Step 2: Divide both sides by 2
\[
\frac{2y}{2} = \frac{16}{2}
\]
\[
y = 8
\]

### Solution: \( y = 8 \)

Would you like more details or have any questions? 

Here are some related questions:
1. How do you solve equations with variables on both sides?
2. What happens if the equation includes fractions?
3. How do you solve inequalities?
4. What if you want to check if the solution is correct?
5. Can this method be applied to more complex equations?

**Tip:** Always isolate the variable step by step to make the equation easier to solve!

Learn how to solve the linear equation 2y + 12 = 28 with a clear step-by-step solution. This problem demonstrates how to isolate variables and apply inverse operations, a key concept in algebra. Suitable for students in Grades 6-8.

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