To solve the equation \( (2x - 20)^\circ = 112^\circ \):

1. Start by isolating \( 2x \):
   \[
   2x - 20 = 112
   \]
   
2. Add 20 to both sides:
   \[
   2x = 112 + 20
   \]
   \[
   2x = 132
   \]
   
3. Divide both sides by 2 to solve for \( x \):
   \[
   x = \frac{132}{2}
   \]
   \[
   x = 66
   \]

Thus, the solution is \( x = 66 \).

Would you like more details or have any questions?

Here are 5 related questions you might find helpful:
1. What if the equation was \( (3x - 15)^\circ = 95^\circ \)?
2. How would you solve \( 4x + 10^\circ = 180^\circ \)?
3. Can you solve the equation \( 5x - 25^\circ = 100^\circ \)?
4. How does this approach change when dealing with inequalities like \( 2x - 20 < 112 \)?
5. What if the equation involved fractions like \( \frac{2x - 20}{2} = 56^\circ \)?

**Tip:** Always perform the same operation on both sides of an equation to maintain balance!

Discover how to solve the linear equation (2x - 20)° = 112° using basic algebraic methods. This step-by-step guide is designed for students in Grades 6-8, covering key concepts like isolating variables and using the properties of equality.

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