The difference of 3 times a number and 1 is -14. Find the number.

Let's denote the unknown number by \( x \).

The problem states: "The difference of 3 times a number and 1 is -14."

This can be translated into the equation:

\[ 3x - 1 = -14 \]

To find \( x \), we need to solve this equation. Here are the steps:

1. Add 1 to both sides of the equation to isolate the term with \( x \):

\[ 3x - 1 + 1 = -14 + 1 \]

\[ 3x = -13 \]

2. Divide both sides by 3 to solve for \( x \):

\[ x = \frac{-13}{3} \]

So, the number is \( x = -\frac{13}{3} \).

Would you like more details on this solution or have any questions?

Here are 5 more questions you might want to ask:
1. How do you solve quadratic equations?
2. Can you explain the Pythagorean theorem?
3. What is the derivative of \( x^2 \)?
4. How do you find the area of a circle?
5. What is the formula for compound interest?

Tip: When solving equations, always perform the same operation on both sides to maintain the equality.

Learn how to solve the equation involving 3 times a number and 1, resulting in -14. This problem covers key algebraic concepts, including linear equations. Suitable for students in Grades 7-9.

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