Math Problem Statement
Solution
Let's start by solving the questions step by step.
1. Solving the equation:
Step 1: Subtract 4 from both sides to isolate the term with .
Step 2: Multiply both sides by 3 to solve for .
So, is one solution. Now, let's check the answer choices:
- Option C: is a correct answer.
Since the problem asks to select all that apply, we know that other choices might also work. Let's verify:
- Option B:
- Option D:
- Option E:
- Option F:
None of these additional values satisfy the equation, so only C: is correct.
2. Isolate the absolute value expression in the equation:
Step 1: Subtract 3 from both sides.
Step 2: Divide by -3 to isolate the absolute value.
Since the absolute value cannot equal a negative number, there is no solution to this equation.
3. Isolate the absolute value expression in the equation:
Step 1: Add 3 to both sides.
Step 2: Divide by 5 to isolate the absolute value.
Step 3: Solve for by setting up two cases, since the absolute value can be positive or negative.
-
Case 1:
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Case 2:
So, the solutions to the equation are and .
Summary of Solutions:
- (Option C) is the only solution for the first equation.
- No solution for the second equation.
- The solutions for the third equation are and .
Would you like more details on any of these steps? Here are five follow-up questions you can explore:
- How do we handle equations involving fractions?
- Why can't absolute value expressions equal negative numbers?
- What happens if an absolute value equation has no solution?
- How do you check if your solutions are correct in multi-step problems?
- Can we always have more than one solution for absolute value equations?
Tip: When solving equations involving absolute values, always remember to set up two cases—one for the positive and one for the negative scenario.
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Math Problem Analysis
Mathematical Concepts
Algebra
Absolute Value Equations
Linear Equations
Formulas
Linear equation: ax + b = c
Absolute value: |a| = b
Theorems
For |x| = b, the solution is x = b or x = -b
Isolate the absolute value before solving the equation
Suitable Grade Level
Grades 6-8