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### Problem 4 (Jacket Prices):
- Let \( A \) be the price of jacket A and \( B \) be the price of jacket B.

The two equations based on the problem are:
1. \( 3A + 2B = 370,000 \)
2. \( 2A + 5B = 430,000 \)

We can solve this system of equations to find the price of each jacket.

#### Solving the system:
1. First, multiply the first equation by 5 and the second by 2 to eliminate \( B \):
   \[
   5(3A + 2B) = 5(370,000) \implies 15A + 10B = 1,850,000
   \]
   \[
   2(2A + 5B) = 2(430,000) \implies 4A + 10B = 860,000
   \]

2. Subtract the second equation from the first:


Harga 3 jaket A dan 2 jaket B adalah Rp 370.000. Harga 2 jaket A dan 5 jaket B adalah Rp 430.000. Berapa harga jaket masing-masing?

Learn how to solve a system of linear equations to determine the price of jackets. This example uses elimination and substitution methods, covering algebraic concepts. Suitable for students in Grades 9-11.

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