Math Problem Statement

Which of the following equations require the use of logarithms to solve for the given variable? Select ALL that apply. Answer Options Elimination Tool Select all that apply A A = 10,000 ( 1.01 ) 13 B 25,000 = 10,000 ( 1.01 ) 2 t C 1,000 ( .55 ) x = 4 D 1,000 ( x ) 4 = 14 E 1,400 0 = 2 3 ( 1 + .05 12 ) 12 t Next Question Submit answer Copyrig

Solution

To determine which equations require logarithms to solve for the given variable, we need to identify cases where the variable is in the exponent.

Let's analyze each option:

  • (A) A=10,000(1.01)13A = 10,000 (1.01)^{13}

    • The exponent is a constant (13), so no logarithms are needed.
    • Not a correct choice.
  • (B) 25,000=10,000(1.01)2t25,000 = 10,000 (1.01)^{2t}

    • The variable (tt) is in the exponent.
    • To solve for tt, we take the logarithm.
    • Correct choice.
  • (C) 1,000(0.55)x=41,000 (0.55)^x = 4

    • The variable (xx) is in the exponent.
    • To solve for xx, we take the logarithm.
    • Correct choice.
  • (D) 1,000(x)4=141,000 (x)^4 = 14

    • The variable (xx) is the base, not the exponent.
    • Solve by taking the fourth root, not logarithms.
    • Not a correct choice.
  • (E) 1,400=23(1+.0512)12t1,400 = \frac{2}{3} (1 + \frac{.05}{12})^{12t}

    • The variable (tt) is in the exponent.
    • To solve for tt, we take the logarithm.
    • Correct choice.

Final Answer:

(B), (C), and (E) require logarithms to solve.

Would you like a step-by-step solution for one of these?

Related Questions:

  1. How do logarithms help solve exponential equations?
  2. Can you solve 5x=205^x = 20 using logarithms?
  3. What is the logarithmic form of ab=ca^b = c?
  4. How do you use the natural logarithm (ln) to solve for exponents?
  5. What is the difference between log and ln?

Tip:

To solve an equation of the form ax=ba^x = b, use logarithms:
x=logblogax = \frac{\log b}{\log a}

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Math Problem Analysis

Mathematical Concepts

Exponential Equations
Logarithms

Formulas

a^x = b → x = log(b) / log(a)

Theorems

Properties of Logarithms

Suitable Grade Level

Grades 10-12