Math Problem Statement

Give me 5 questions with Specific PMFS (e.g. x: 0, 1 P(x) = .... ) wher i must find E(X) or Var(X) after derriving MGF, put the oslutoons below

Solution

Here are five questions involving specific probability mass functions (PMFs) where you need to find the expected value E(X)E(X) and variance Var(X)\text{Var}(X) after deriving the moment generating function (MGF):


1. Question 1:

Given the following PMF:

  • x:0,1x: 0, 1
  • P(X=0)=0.6P(X=0) = 0.6
  • P(X=1)=0.4P(X=1) = 0.4

Find:

  • (a) The MGF MX(t)M_X(t).
  • (b) E(X)E(X) and Var(X)\text{Var}(X).

2. Question 2:

Given the following PMF:

  • x:0,1,2x: 0, 1, 2
  • P(X=0)=0.3P(X=0) = 0.3
  • P(X=1)=0.5P(X=1) = 0.5
  • P(X=2)=0.2P(X=2) = 0.2

Find:

  • (a) The MGF MX(t)M_X(t).
  • (b) E(X)E(X) and Var(X)\text{Var}(X).

3. Question 3:

Given the following PMF:

  • x:1,0,1x: -1, 0, 1
  • P(X=1)=0.2P(X=-1) = 0.2
  • P(X=0)=0.5P(X=0) = 0.5
  • P(X=1)=0.3P(X=1) = 0.3

Find:

  • (a) The MGF MX(t)M_X(t).
  • (b) E(X)E(X) and Var(X)\text{Var}(X).

4. Question 4:

Given the following PMF:

  • x:1,2,3x: 1, 2, 3
  • P(X=1)=0.2P(X=1) = 0.2
  • P(X=2)=0.5P(X=2) = 0.5
  • P(X=3)=0.3P(X=3) = 0.3

Find:

  • (a) The MGF MX(t)M_X(t).
  • (b) E(X)E(X) and Var(X)\text{Var}(X).

5. Question 5:

Given the following PMF:

  • x:0,2,4x: 0, 2, 4
  • P(X=0)=0.3P(X=0) = 0.3
  • P(X=2)=0.4P(X=2) = 0.4
  • P(X=4)=0.3P(X=4) = 0.3

Find:

  • (a) The MGF MX(t)M_X(t).
  • (b) E(X)E(X) and Var(X)\text{Var}(X).

Solutions


Solution 1:

  1. MGF: MX(t)=0.6e0t+0.4e1t=0.6+0.4etM_X(t) = 0.6e^{0t} + 0.4e^{1t} = 0.6 + 0.4e^t
  2. Expected value: E(X)=MX(0)=0.4E(X) = M_X'(0) = 0.4
  3. Variance: Var(X)=MX(0)[MX(0)]2=0.24\text{Var}(X) = M_X''(0) - [M_X'(0)]^2 = 0.24

Solution 2:

  1. MGF: MX(t)=0.3e0t+0.5e1t+0.2e2t=0.3+0.5et+0.2e2tM_X(t) = 0.3e^{0t} + 0.5e^{1t} + 0.2e^{2t} = 0.3 + 0.5e^t + 0.2e^{2t}
  2. Expected value: E(X)=MX(0)=0.9E(X) = M_X'(0) = 0.9
  3. Variance: Var(X)=MX(0)[MX(0)]2=0.49\text{Var}(X) = M_X''(0) - [M_X'(0)]^2 = 0.49

Solution 3:

  1. MGF: MX(t)=0.2et+0.5e0t+0.3et=0.2et+0.5+0.3etM_X(t) = 0.2e^{-t} + 0.5e^{0t} + 0.3e^{t} = 0.2e^{-t} + 0.5 + 0.3e^{t}
  2. Expected value: E(X)=MX(0)=0.1E(X) = M_X'(0) = 0.1
  3. Variance: Var(X)=MX(0)[MX(0)]2=0.71\text{Var}(X) = M_X''(0) - [M_X'(0)]^2 = 0.71

Solution 4:

  1. MGF: MX(t)=0.2e1t+0.5e2t+0.3e3t=0.2et+0.5e2t+0.3e3tM_X(t) = 0.2e^{1t} + 0.5e^{2t} + 0.3e^{3t} = 0.2e^t + 0.5e^{2t} + 0.3e^{3t}
  2. Expected value: E(X)=MX(0)=2.1E(X) = M_X'(0) = 2.1
  3. Variance: Var(X)=MX(0)[MX(0)]2=0.49\text{Var}(X) = M_X''(0) - [M_X'(0)]^2 = 0.49

Solution 5:

  1. MGF: MX(t)=0.3e0t+0.4e2t+0.3e4t=0.3+0.4e2t+0.3e4tM_X(t) = 0.3e^{0t} + 0.4e^{2t} + 0.3e^{4t} = 0.3 + 0.4e^{2t} + 0.3e^{4t}
  2. Expected value: E(X)=MX(0)=2.2E(X) = M_X'(0) = 2.2
  3. Variance: Var(X)=MX(0)[MX(0)]2=1.36\text{Var}(X) = M_X''(0) - [M_X'(0)]^2 = 1.36

Follow-up Questions:

  1. Can you derive the MGF for a binomial distribution with n=2n = 2 and p=0.5p = 0.5?
  2. What is the relation between the MGF and the characteristic function of a random variable?
  3. How does the second derivative of the MGF at t=0t = 0 relate to variance?
  4. How would you compute the MGF for a Poisson distribution?
  5. Can you find E(X)E(X) and Var(X)\text{Var}(X) for a geometric distribution using the MGF?

Tip: When deriving the MGF, remember that it is the expectation of etXe^{tX}, so carefully substitute the values of XX and compute the sum.

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Math Problem Analysis

Mathematical Concepts

Probability Theory
Moment Generating Function (MGF)
Expected Value
Variance
Probability Mass Function (PMF)

Formulas

Moment Generating Function: M_X(t) = E(e^{tX})
Expected Value from MGF: E(X) = M'_X(0)
Variance from MGF: Var(X) = M''_X(0) - [M'_X(0)]^2

Theorems

Properties of Moment Generating Functions
Definition of Expected Value and Variance

Suitable Grade Level

Grades 11-12, Undergraduate