Find the solution(s) of the following equation.
\[c^2 = 121\]

The given equation is:

\[
c^2 = 121
\]

To find the solution(s), take the square root of both sides of the equation:

\[
c = \pm \sqrt{121}
\]

Since \(\sqrt{121} = 11\), we have:

\[
c = \pm 11
\]

Therefore, the solutions are:

\[
c = 11 \quad \text{or} \quad c = -11
\]

Would you like any further details or clarifications? Here are 5 related questions for further exploration:

1. How do we solve equations with higher powers, such as \(c^3 = 8\)?
2. What happens if we solve \(c^2 = -121\)?
3. Can we solve \(c^2 = 0\) the same way?
4. What is the difference between a positive and negative square root?
5. How does this approach apply to solving quadratic equations?

**Tip:** Always consider both the positive and negative roots when solving \(x^2 = a\), unless further restrictions are given.

Discover how to solve the equation c^2 = 121 using the square root method. This problem focuses on basic algebra and solving equations with square roots. Suitable for students in Grades 6-8.

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